Introduction:
Thevenin Equivalents help us to model linear circuits as a single resistor and power supply. We performed an experiment that proves the validity of Thevenin equivalent circuits.
Objective:
Test a complicated circuit and measure voltage and current readings through a load, then replace with the thevenin equivalent circuit and measure the voltage and current readings Analyze and interpret the data and perform any error analysis if necessary.
Procedure:
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This is our original circuit diagram We decided to perform some calculations to find thevenin voltage and resistance.
V1 = V2 = 9V ; Cable 1 (C1) = 100 Ohm ; Cable 2 ((C2) = 39 Ohm ; Cable 3 (C3) = 39 Ohm ; Load 1 (L1) = 680 Ohm ; Potential drop across Load 2 = 8V
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Thevenin Voltage = |
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Thevenin Resistance / Norton Current |
Now that we figured out our thevenin voltage and current, we consider multiple situations for the thevenin circuit.
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Required resistance for a potential drop of 8 volts (minimum resistance) |
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Current through the thevenin equivalent circuit with no load. |
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Potential drop through load with infinite resistance. |
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Our Resistors |
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Setup with resistor boxes |
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Resistor box and power supply measurements for the thevenin equivalent, theoretical vs actual |
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Measured voltage vs Theoretical Voltage through the Potentiometer |
The results seem to match our predictions on paper within reasonable uncertainty taking into account the differences in our theoretical to actual measurements.
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We use the same materials, but with more wires and other necessities for the unthevinized circuit.
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Resistor and voltage measurements for our un-thevinized circuit.
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The results |
The potential drop through the load and also the current matches with our thevenin circuit.
Finally, we will verify that the power supplied is maximized by the formula P = Vth^2/4Rth
Conclusion: The thevenin equivalent allows us to lessen our troubles in calculation when we plug things into a linear ciruit.
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